Un circuito que contiene una batería de 6.0 V se conecta con un resistor de 81.0 Ω. Si después de media hora el voltaje de la batería disminuye a 4.5 V, cómo cambia la corriente en el circuito respecto al principio

AI = 0.019 A

Explanation:

The computation of the current change and the same compared to the staring is shown below;

I = v ÷ R

= 5v ÷ 81.0

I = 0.074 A

Now  

I = v ÷ r

= 6v ÷ 81.0

I = 0.055A

Now

I = 0.074A - 0.055A

AI = 0.019 A

The same would be considered

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d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day