A train is uniformly accelerated and passes Successive kilometre Stones with velocities of
18 km/h and 36 km/h respectively
, calculate
the velocity, when it passes the third kilometre
Stone. Also find the time taken for each of
these two intervals of one kilometre​

Explanation:

18 km/hr(1000 m/km) / (3600 s/hr) = 5 m/s

36 km/hr = 10 m/s

v² = u² + 2as

a = (v² - u²)/2s

a = (10² - 5²)/2(1000) = 0.0375 m/s²

v² = 10² + 2(0.0375)(1000)

v² = 175

v = 13.22875... ≈ 13 m/s ≈ 48 km/hr

v = u + at

t = (v - u) / a

t = (10 - 5)/0.0375 = 133.333... 133 s

t = (13.22875 - 10) / 0.0375 = 86.1 s

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

reserve is the answer