Two cars collide and lock together on wet pavement, the coefficient of friction of tires on wet pavement is 0.250. Car 1 is 1310 kg and Car 2 is 1810 kg. Car 1 is traveling at 16.9 m/s and Car 2 is traveling at 22.4 m/s

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

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