It takes 100 J of work to move 2.2 C of charge from the negative plate to the positive plate
of a parallel plate capacitor.
What voltage difference exists between the
plates?
Answer in units of V.

Gravity bc it’s gravity

Is there a picture to go along with this

It really doesn't matter for any of the questions that you've listed.

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.