9.Water flows'along a horizontal pipe of cross sectional area 48cm2 which has a constriction of cross sectional area 12cm2 at one place. If the speed of the water at the constriction is 36m/s,
calculate the speed in the wider section,
(3mk)
​

3.2x10^7

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m

no

explanation:

no i dont know how to solve this you should probably try to google the answer