During a car crash test, a car of mass 1200 kg is sent down a horizontal track at a constant velocity of 30 m/s. The car strikes a barrier that compresses until the car comes to a stop. This is very similar to a compressed spring. If the car comes to a stop in 0.25 seconds and the spring compresses 1.75 m, what power was needed to stop the car AND what was the spring constant of the barrier? A k = 352,700 N/m; P = 540,000 W
B k = 617,100 N/m; P = 2,160,000 W
C k = 617,100 N/m; P = 540,000 W
D k = 352,700 N/m; P = 2,160,000 W

Answer the radiant sun;

Your answer would be false

To compare speeds speeds of wagons we will use second newton's law. it states: f = m * ahere we can see that force depends on the acceleration. if we know acceleration for both wagons we can compare them to make conclusion of speeds of wagons.we have: m1 = 10lbm2 = 20lbf1 = 2*f2also: m2 = 2*m1for bill we have equation: f1 = m1 * a1for tom we have equation: f2 = m2 * a2after inserting identities we have: 2*f2 =m1 * a1f2 = 2*m1 * a2in order to make conclusions about speeds we will solve these equations for a and find their ratio: a1 = 2f2 / m1a2 = f2 / 2m1a1 / a2 = (2f2/m1) / (f2/2m1)a1 / a2 = (2f2*2m1) / (m1*f2)a1 / a2 = (4f2m1) / (m1f2)a1 / a2 = 4this ratio is bigger than 1 and this means that a1 is greater than a2. a1 is 4 times greater than a2. speed of bill's wagon is 4 times greater than speed of tom's wagon.