Physics, 01.05.2021 22:50 CoolRahim9090

A rocket is in motion in space. There are no unbalanced forces acting on it. What will the rocket do?
A. remain in motionat a constant velocity
B. change direction
C. come to a stop
D. change speed

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Answer from: Quest

we have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is $[2,\infty)$ .

if we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

let us know find its inverse.

$y=(x-5)^{2}+2$

upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

let us now solve this function for y.

$(y-5)^{2}=x-2\\ y-5=\pm \sqrt{x-2}\\ y=5\pm \sqrt{x-2}\\$

hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

Answer from: Quest

blue light is scattered in different directions by the tiny molecules of air. blue is scattered more than other colours because it has a shorter distance to travel which results in smaller waves. this is why we see a blue sky most of the time.

Answer from: Quest

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2

Answer from: Quest

Part a: using momentum conservation we have: direction x: (15) (7.0) + 0 = (15) (4.2) cos (-20 °) + (10) v₂ (f) cosθ (10) v₂ (f) cosθ = (15) (7.0) - (15) (4.2) cos (-20 °) (eq 1) direction y: 0 + 0 = (15) (4.2) sin (-20 °) + (10) v₂ (f) sinθ (10) v₂ (f) sinθ = - (15) (4.2) sin (-20 °) (eq 2) we divide both equations (1) and (2): left side: (10) v₂ (f) sinθ / (10) v₂ (f) cosθ = tanθ right side: - (15) (4.2) sin (-20 °) / (15) (7.0) - (15) (4.2) cos (-20 °) clearing the angle we have: θ = tan⁻¹ [- (15) (4.2) sin (-20 °) / (15) (7.0) - (15) (4.2) cos (-20 °)] θ = 25 ° we use any of the equations to find the speed. from (2) we have: (10) v₂ (f) sinθ = - (15) (4.2) sin (-20 °) v₂ = - (15) (4.2) sin (-20 °) / (10) sin25 ° answer: v₂ = 5.1m / s note: θ = 25 ° (direction is in the first quadrant, north of east) part b: initial kinetic energy: k (i) = 0.5 (15) (7.0) ² = 370j (rounded) final kinetic energy: ke (f) = 0.5 (15kg) (4.2m / s) ² + 0.5 (10kg) (5.1m / s) ² = 260j (rounded) answer: a difference of 110j, so it was an inelastic collision.

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A rocket is in motion in space. There are no unbalanced forces acting on it. What will the rocket...

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