‏If the equivalent dose is 0.7 mSv for the slow ‏neutron. What is the absorbed dose in mrad?
‏(where RBE for slow neutron 4 rem/rad and 1
‏rem = 0.01 Sv).

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer