In the absence of air friction, an object dropped near the surface of the Earth experiences a constant acceleration of about 9.8 m/s? This means that the O object falls 9.8 meters during the first second only
O speed of the object as it falls is 9.8 m/s.
rate of change of the displacement with respect to time for the object equals 9.8 m/s?.
O speed of the object increases 9.8 m/s during each second
O object falls 9.8 meters during each second

he . if i may ask what i your question exactly?

explanation:

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

a=d/t

a="triangle"v/t

explanation:

a = acceleration