A mercury in barometer shows a height of 70cm. What height would be shown in the barometer at the same place if water density 1.0×10³kg/m³ is used(denssity of mercury=13600kgm-³)​

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0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2

no

explanation:

no i dont know how to solve this you should probably try to google the answer