n Figure 10.6, a mass of 81.90 kg is attached to a light string which is wrapped around a cylindrical spool of radius 10 cm and moment of inertia The spool is suspended from the ceiling, and the mass is then released from rest a distance 2.60 m above the floor. How long does it take to reach the floor?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.