Calculate the rate constant for the first-order decay of 24na (t1/2 = 14.7 h).

This problem is pretty straight forward since we are given the half time and we simply have to find for the rate constant. The equation relating the two variable is:

t1/2 = ln(2) / k

where k is the rate constant, therefore:

k = ln(2) / t1/2

k = ln(2) / 14.7 h

k = 0.047 / hour

it should be -8.6 cm hope this out

heats surface water up