What is the acceleration due to gravity at an altitude of 116?

Gravitational acceleration (Ga) is  inversely proportional to  k / Distance^2

so Ga * Distance^2 = K

On the surface of Earth acceleration due to gravity is about 9.8m/s^2 with an average distance to the earths core of about 6371 km (Wolfram alpha).

So k = 9.8 * 6371^2
I'm presuming that your distance of 116 is km

As 
Ga = k / distance^2 

Ga = ((9.8 * 6371^2) / (6371 + 116)^2 ) = 397778481.8 / 42081169

= 9.45 m/s^2 to 2sf

Ibelieve your answer is b.hope this : )