Adrag racer, starting from rest, speeds up for 402 m with an acceleration of +25.0 m/s/s. a parachute then opens, slowing the car down with an acceleration of -5.95 m/s/s. how fast is the racer moving 325 m after the parachute opens?

After 402 metres the drag reach a maximum speed according the formula: Vf=(Vi^2+2*a*d)^1/2, where Vf is final speed, Vi is initial speed, a is acceleration and d is distance. So then: Vf=(0^2+2*25*402)^1/2=141.77 m/s From that point the drag starts to brake, then with the same formula: Vf=(141.77^2+2*(-5.95)*325)^1/2=127.41 m/s After 325 meter of parachute opens, the drag still moves at 127.41 m/s

The objects do not reach terminal velocity         there is not enough time from the time the object falls from when it hits the ground to achieve terminal velocity. an object must be placed higher to achieve terminal velocity in order to be in free fall.