Physics, 29.11.2019 01:31 franklynvaldez01

The idea that the same geological processes that happen today have been happening throughout history is called

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Answer from: Lydiac9243

Uniformitarianism is the answer.

Hope it helps.

Answer from: mari256650

Law of Uniformitarianism

Explanation: According to the law of Uniformitarianism, the earth dynamic geological process that undergoes now, must have taken place in the past in the same way and at the same speed as well as intensity. This also is believed that the same processes will also take place in the future.

This changes takes place over millions of years and this is how the different features, structures and landforms have formed and evolved on earth due to the weathering and erosion of the rocks on the surface. In addition to that, plate tectonic movement, eruption from the volcanoes, earthquakes and tsunamis are also responsible for the formation of the present day scenerio.

Answer from: Quest

okay i have so many questions. but the big one here is: um wt..f is this mess? ?

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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