What is the temperature change in 355 ml of water upon absorption of 34 kj of heat? (the specific heat capacity of water is 4.184 j/g∘c.) express your answer in degrees celsius?

Heat gained or absorbed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)

We have to determine the value of (T2-T1) which is the temperature change. To do this, we simply substitute the values given above. We do as follows:

Heat = mC(T2-T1)

34 kJ ( 1000 J / kJ ) = 355 mL ( 1 g / mL ) (4.184 J / g-C ) (T2-T1)

(T2-T1) = 22.89 degrees Celsius or Kelvin

THerefore, the temperature change of the abosrption of 34 kJ of heat by water would be 22.89 degrees Celsius.

15.3 cos 65 degrees trig

the higher the current the higher the mag field around it the higher the influence on the compass