Rory uses a battery to power a light bulb with a resistance of 10 ω. if 0.15 a of current is flowing, what is the voltage of the battery?

U=I*R=0.15 [A]* 10 [Ω]=1.5 [V] sorry a bit late but this is it

Explanation :

Given that, Rory uses a battery to power a light bulb with a resistance of 10 Ω. We have to find the voltage

For current, we can use the Ohm's law.

Mathematically, it can be written as:

V =I R

V = 1.5 Volts

So, the voltage of the battery is 1.5 volts.

Hence, this is the required solution.

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz