What is the value of the composite constant (gmer2e), to be multiplied by the mass of the object mo in the equation above? express your answer numerically in meters per second per second?

The solution would be like this for this specific problem:

F = (G Me Mo) / Re^2 

F / Mo = (G Me) / Re^2 

G = gravitational constant = 6.67384 * 10^-11 m3 kg-1 s-2 

Me = 5.972 * 10^24 kg 

Re^2 = (6.38 * 10^6)^2 m^2 = 40.7044 * 10^12 m^2 = 4.07044 * 10^13 m^2 

G Me / Re^2 = (6.67384 * 10-11 * 5.972 * 10^24) / 4.0704 * 10^13 = 9.7196 m/s^2 

9.7196 m/s^2 = acceleration due to Earth’s gravity 

Therefore, the value of the composite constant (Gme / r^2e) that is to be multiplied by the mass of the object mo in the equation above is 9.7196 m/s^2.

small = small current large mag large current

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.