How much less power is wasted if the electricity is delivered at 50,000 v rather than 12,000 v?

We are asked in this problem to determine the power wasted given the two voltages: 50,000 and 12,000 volts. By physics, the formula to determine power using volts is expressed as P = VI where P is in watts, V is in volts and I, current, is in Amperes. In this case, we just have to plug the given data to the equation named. 

1) P1 = 50,000*I
2) P2 = 12,000 * I

P1 - P2 = (50,000-12,000)*I 
ΔP = 48,000 I 
So the power wasted then is equal to 48,000 times the current employed to achieve power. I should be specified as well to determine the exact difference.

Kinetic energy = 1/2mv^2. since the mass is constant we can form a ratio of it's kinetic energy at 60 divided by that at 30 to see ke(60)/ke(30) = +(60^2)/30^2). this may be said to 300% increase.