On a farm, you are pushing on a stubborn pig with a constant horizontal force with magnitude 30.0 n and direction 37.0° counterclockwise from the +x-axis. how much work does this force do during a displacement of the pig that is (a) s s = 15.00 m2nd; (b) s s = ? 16.00 m2ne; (c) s s = ? 12.00 m2nd + 14.00 m2ne?

Since the force is applied at an angle from the horizontal, we will use the horizontal component of this force in calculating for the displacements.
From derivation, the Fx is:

Fx = F cos φ

Where:

Fx = is the horizontal component of the force

F = total force

φ = angle in radian = 37 * pi / 180 = 0.645 rad

Calculating: Fx = 30.0 N * cos(0.645)

Fx = 23.97 N = 24 N

Calculating for Work: W = Fx * d

A. W = 24 N * 15 m = 360 N

B. W = 24 N * 16 m = 384 N

C. W = 24 N * 12 m = 288 N

D. W = 24 N * 14 m = 336 N 

answer; the correct answer is technician a; ///100%good luck

f=ma newton

f=100x2.5=250n