Aroom of volume v contains air having equivalent molar mass m. if the temperature of the room is raised from t1 to t2, what mass of air will leave the room

The ideal gas law is:

pV = nRT

where p=pressure, V=volume, n=number of moles, R=gas constant, T=temperature, m=molar mass, M=mass

Setting up for M1 and M2 using the fact that n = M/m

pV1 = M1/m x RT1 ==> M1 = PmV1/RT1 
pV2 = M2/m x RT2 ==> M2 = PmV2/RT2 

Since volume doesn't change, V1 = V2 =V

The question is to find for the mass of air that enters the room, which is M2 – M1

M2 – M1 = (PmV2/RT2) – (PmV1/RT1 )

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .

f=ma newton's second law 7x8=56n