Did you detect a difference in the radiation levels between the intact smoke detector and the americium-241 removed from the smoke detector? if so why do you think the smoke detector is designed with that difference?

Lab results:

Smoke detector = 40.0 cpm Geiger counter

Americium-241 = 10,400 cpm Geiger counter

The great difference in the radiation level means that Americium-241 is more radioactive than the smoke detector itself. Americium-241 is used as a source of alpha radiation. This radiation ionizes the air particles inside the smoke detector allowing it to conduct small amounts of electric current. For example, if smoke particles go inside the smoke detector, these are hit by alpha radiation and thus causing a drop in current. The drop in current is detected by the smoke detector which then sets off the alarm.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

object 2 because all the other ones are wrong