Aspacecraft is launched from earth toward the moon. where will the spacecraft be when the gravitational forces acting on it are equal? a. closer to earth than to the moon because the moon has greater mass than earth. b. closer to the moon than to earth because the moon has greater mass than earth. c. closer to earth than to the moon because earth has greater mass than the moon. d. closer to the moon than to earth because earth has greater mass than the moon.

D. Closer to the moon than to Earth because Earth has greater mass than the moon.

Explanation:

The force of gravity being exerted by any object depends on its mass. More the mass greater will be force of gravity. Also, the range of the gravitational force will be more for the object with more mass.

Here since Earth is heavier than the Moon, its gravitational force will be huge even at large distances as compared to the Moon.

That is why when the spacecraft experiences equal gravitational force it will be closer to the Moon than Earth as Earth is heavier than Moon.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

total distance/total time

(85 + 82)/(5+3)

167/8

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