If a photon has a frequency of 5.20 × 1014 hertz, what is the energy of the photon? given: planck's constant is 6.63 × 10-34 joule·seconds.

So we want to know the energy of a photon that has a frequency f=5.2*10^14 Hz. The equation for energy of a photon is E=h*f where E is energy, h= 6.63*10^-34 is the Planck's constant and f is the frequency. So lets input the numbers:

E=h*f= (6.63*10^-34)*(5.2*10^14)=

E=(6.63*5.2)*10^(-34+14)= 34.478*10^-20=3.4478*10^-19 J. 

So a photon has the energy E=3.4478*10^-19 J. 

B) raising the temperature and reducing the volume of the gas.|-/ 

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