Aphoton with a wavelength of 2.29x10^-7 meters strikes a mercury atom in the ground state. the photon can be absorbed by the mercury atom because it will accommodate an energy level jump to

I just figured this out now.
First you would use the formula
Ephoton= hc/λ and substitute in the value's of plank's constant, the speed of light in a vaccum and the wavelength which will give you the energy in joules. Then you go to the reference table and solve for the energy used between the different levels for Mercury making sure to convert electron volts to jules. In the end the correct answer should be energy level D.

What do you need on