You add 400 ml of water at 30c to 100 ml of water at 80c. what is the most likely final temperature of the mixture? a. 110c b. 50c c. 20c d. 40c

Problem: What is the most likely final temperature of the mixture
Given: m1 =400ml                                                         m2=100ml
            c1= 4.18J/g∘C   (specific heat of water)           c2=4.18J/g∘C 
            T1=30C                                                              T2=80C

Solution: Formula: T = ( m1c1T1 + m2c2T2 ) / ( m1c1 + m2c2 )
         
           [(400)(4.18)(30)+(100)(4,18)(80)] /[(400)(4.18)+(100)(4.18)]
         
           =[(50,160)+(33,440)] / [(1672)+(418)]
 
           =83,600/2090
  
  Answer =40C