Aflywheel of radius 0.46 m and moment of inertia of 17 kg · m2 rotates initially at a rate of 4.4 rev/s. if a force of 3.2 n is applied tangentially to the flywheel to slow it down, how much work will be done by this force in bringing the flywheel to a stop?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.