On mars, where air resistance is negligible, an astronaut drops a rock from a cliff and notes that the rock falls about d meters during the first t seconds of its fall. assuming the rock does not hit the ground first, how far will it fall during the first 4t seconds of its fall?

Explanation:

As we know that initial speed of the fall of the stone is ZERO

also the acceleration due to gravity on Mars is g

so we have

now we have

now if the same is dropped for 4t seconds of time

then again we will use above equation

c. newton's third law of motion

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.