Amagnetic hockey puck (0.40 kg) hits another hockey puck (0.40 kg) at rest and both travel together to the right at 8.0 m/s. how fast was the first hockey puck initially moving?

m/s

Answer

= 16 m/s

Explanation

The law conservation of energy states that, momentum before collision is equal to momentum after collision.

m₁v₁ = m₂v₂

momentum before collision = (0.40 × v) + (0.40 × 0)

= 0.4v Km/s

momentum after collision = (0.40+0.40) × 8.0

= 0.8 ×8.0

= 6.4 Km/s

m₁v₁ = m₂v₂

0.4v Km/s = 6.4 Km/s

v = 6.4/0.4

= 16 m/s

they should be similar or the same

wavelength divides in half and speed stays the same.