A0.321-kg mass is attached to a spring with a force constant of 12.3 n/m. if the mass is displaced 0.256 m from equilibrium and released, what is it's speed when it is 0.128 m from equilibrium?

Speed, v = 1.37 m/s

Explanation:

Given that,

Mass of the object, m = 0.321 kg

Force constant, k = 12.3 N/m

Amplitude, A = 0.256 m

Position from equilibrium, x = 0.128 m

To find,

The speed of the object.

Solution,

The velocity of the object that is executing SHM is given by :

v = 1.37 m/s

So, the speed of the object is 1.37 m/s.

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