In a particular location, the horizontal component of the earth's magnetic field has a magnitude of 1.50 10-5 t. an electron is shot vertically straight up from the ground with a speed of 2.40 106 m/s. what is the magnitude of the acceleration caused by the magnetic force? ignore the gravitational force acting on the electron.

Acceleration is the time rate of change of velocity. Acceleration is a vector, so this means it has both magnitude and direction. The length of the vector is its magnitude. Its direction is the direction of the vector.

The magnitude of the force is F=qvB.

According to Newton’s second law: F=ma, where m is the mass of the object, and a is its acceleration.

So, F=ma=qvB => a=F/m ,

a=qvB/m,

m in our case is the mass of an electron m=9.1x10^-31.

a= 1.60x10^-19C*2.40x10^6m/s*1.50x10^-5T/9

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