A−6.30-d lens is held 14.5cm from an ant 1.00mm high.
find the image distance. follow the sign conventions.
express your answer to three significant figures and include the appropriate units.

f = 1/D

f = 1/6.3 = 15.87cm

1/f = 1/v - 1/u --> 1/v = -1/f - 1/u --> 1/v = -1/15.87 - 1/14.5 = -0.131977

(-0.131977)^-1 = -7.577

answer: what are you talking about?

explanation:

a, c, d, e are all applying about success strategies.