A1.0-cm-tall object is 80 cm in front of a converging lens that has a 35 cm focal length.

To find the distance of the image, recall that for a converging lens that
1 / f = 1 /d_o + 1/d_i
where f is the focal length, d_o is the object distance and d_i is the image distance.
Thus, 1/35 = 1/80 + 1/d_i
1/d_i = 1/35 - 1/80 = 9/560
d_i = 590/9 = 62.22 cm
Therefore, the distance of the image is 62.22 cm

To find the height of the image, recall that for a converging lens that
h_i/h_o = -d_i/d_o
where h_i is the height of the image, h_o is the height of the object, d_o is the object distance and d_i is the image distance.
Thus, h_i / 1 = -62.22 / 80
h_i = -0.78 cm
Therefore, the image is an inverted image of height 0.78 cm.

Where is the table ? you can take a picture of it