Two frictionless blocks, having masses of 8.0 kg and 1.0 kg, rest on a horizontal surface. if a force applied to the 8.0 kg block gives it an acceleration of 5.0m/s2, then the same force will give the 1.0 kg block an acceleration (in m/s2 of

Acceleration in 1 kg block = a2 = 40 m/s^2

Explanation:

Mass of first block = m1 = 8 kg  

Mass of second block = m2 = 1 kg  

Acceleration in first block = a1 = 5 m/s  

According to newton’s second law of motion,

F1 = m1a1    …….. (i)

As the same force is applied on second block so,

F1 = m2a2   ……… (ii)

Comparing equation (i) and (ii) ,

m1a1 = m2a2

a2 = m1a1/m2

a2 = (8)(5)/1

a2 = 40 m/s^2  

a

explanation:

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two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.