a jet plane is traveling with a velocity of 720 kilometers/hour due north. there is a crosswind of 40 kilometers/hour from the east. find the resultant velocity and the direction of the jet plane.

721.1 km/h, at 86.6 degrees north of west

Explanation:

The magnitude of the velocity of the plane can be found by calculating the resultant of the two velocities:

The direction can be found as follows:

where 720 km/h represents the velocity towards north, while 40 km/h represents the velocity towards west, so the angle is measured with respect to east. Therefore:

the direction is north of west

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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