Agolfer tees off and hits a golf ball at a speed of 31 m/s and at an angle of 35 degrees. what is the vertical velocity component of the ball? round the answer to the nearest tenth of a m/s.

17.8 m/s

Explanation:

v = speed at which the golf ball is hit by the golfer = 31 m/s

θ = angle at which the golf ball is launched = 35 degrees

v' = vertical velocity component of the ball

vertical velocity component of the ball is given as

v' = v Sinθ

inserting the values

v' = 31 Sin35

v' = (31) (0.574)                                     Since Sin35 = 0.574

v' = 17.8 m/s

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