Acar has a mass of 820 kg. it starts from rest and travels 41 m in 3.0 s. what is the force applied to the car?

Assuming constant acceleration, 
s = 1/2 at^2, so 

1/2 * a * 3^2 = 41 
a = 9.111 

And, we all know that F = ma

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward

Caused conformity rates to go down. apex ; )