Acar with a mass of 103 kilograms traveling at a speed of 50 kilometers/hour (13.9 meters/second) collides with a stationary car. the duration of the collision is 1 second. after the collision the speed of the moving car is reduced to 5 kilometers/hour (1.4 meters/second). what is the value of the force involved in the collision?

Force, according to Newton's second law of motion, is calculated through the equation,
                                F = m x a
where F is force, m is mass, and a is acceleration.
We are already given with the mass of 103 kg, we therefore need to solve for the acceleration.
                              acceleration = (13.9 m/s  - 1.4 m/s) / 1 s = 12.5 m/s²
Then, we substitute this value to the equation above.
                                   F = (103 kg) x (12.5 m/s²)
                                     F = 1287.5 N
Thus, the force involved in the collision is approximately 1287.5 N. 

If one were to put the y value into the equation, they could find out what x is for a certain value of y.  putting in the value of y (1), we get the equation: 1=4x-12=4xx=0.5this means that the value of x when why is 1 is x=0.5