How do you find the speed of an object given its mass and kinetic energy (what is the formula)?

   v  =   √ { 2*(KE) ] / m } ; 

Now, plug in the known values for "KE" ["kinetic energy"] and "m" ["mass"] ; 
        
and solve for "v".

Explanation:

The formula is:  KE = (½) * (m) * (v²) ;

  
"Kinetic energy" = (½) * (mass) * (velocity , "squared")

Note:  Velocity is similar to speed, in that velocity means "speed and direction";  however, if you "square" a negative number, you will get a "positive"; since:  a "negative" multiplied by a "negative" equals a "positive".

So, we have the formula:

KE = (½) * (m) * (v²) ;  to solve for "(v)" ; velocity, which is very similar to                                          the "speed"; 

we arrange the formula ;

(KE) = (½) * (m) * (v²) ;  ↔  (½)*(m)* (v²) = (KE) ; 


→ We have:  (½)*(m)* (v²) = (KE)  ; we isolate, "m" (mass) on one side of the equation:

   
→ We divide each side of the equation by: "[(½)* (m)]" ; 

    
           →   [ (½)*(m)*(v²) ] /  [(½)* (m)]  = (KE) / [(½)* (m)] ;

 to get: 

                           →   v²     =   (KE) / [(½)* (m)]
                     
                           →   v²     = 2 KE / m

Take the "square root" of each side of the equation ;

                          →  √ (v²)  =  √ { 2*(KE) ] / m }


                          →     v  =   √ { 2*(KE) ] / m } ; 

Now, plug in the known values for "KE" ["kinetic energy"] and "m" ["mass"]; 
       
and solve for "v".

Not what goes around on earth but the universe too.

Answertraveling around a circular trackexplanation"traveling around a circular track" is the best answer as you could be traveling around a circular track at a constant speed. your velocity would therefore have the same magnitude but will always be constantly direction. since acceleration is the rate of change of velocity, the rate of change will only involve the direction of velocity and not the magnitude.wrong choices: "an object at rest" does not accelerate at all"increasing speed while traveling around a curve" means that the acceleration will not be constant due to only change in direction; it will be constant due to both magnitude and direction"an object in free fall" does not necessarily change direction