A12 volt car battery pushes a charge through the headlight circuit with a resistance of 8.5 ohms. how much current is passing through the circuit

Data:
i (current) = ? (Amps)
R (resistance) = 8.5 Ω
V (voltage) = 12 volts

Formula:


Solving:

Ihope you get it right bro

Kinetic energy = 1/2mv^2. since the mass is constant we can form a ratio of it's kinetic energy at 60 divided by that at 30 to see ke(60)/ke(30) = +(60^2)/30^2). this may be said to 300% increase.