A0.25 kg harmonic oscillator has a total mechanical energy of 4.1 j. if the oscillation amplitude is 20.0 cm, what is the oscillation frequency?

4.6Hz

Explanation:

We first have to derive Oscillation Frequency formula

Maximum velocity = Vmax = wA

Energy = 1/2m(Vmax)²

Energy = 1/2m(wA)²

Frequency = w/2π

Hence,

Oscillation Frequency Formula is given as

F =( 1/2πA)× √2E/m

where in the question,

A = Amplitude = 20.0cm

We convert 20.0cm to meter

100cm = 1m

20cm = ?

= 20÷100 = 0.20m

E = Mechanical energy = 4.1j

m = mass = 0.25kg

Frequency =( 1/2π × 0.20m) × √(2×4.1j)/0.25kg

Frequency = 4.558Hz

Oscillatory frequency approximately is = 4.6Hz

explanation:

as the height from which the ruler was dropped increased, the speed of the ruler at ryan's hand increased.

when it gains or loses electrons