Aman walke towards the bus stop 100 meters away at a constant velocity. he reaches the bus stop in 200 seconds. once at the bus stop, he sits for 500 seconds waiting for the bus. he then realizes he forgot something and runs home at a speed of 2.0 meters/second.

what is the velocity, displacement, and the time?

First:

d = 100 m
t = 200 sec

v = 100/200 = 0.5 m/s

Displacement is zero since he returned to his start point.

t2 = d/v2 = 100/2 = 50 sec

total time = 50 + 200 + 500 = 750 sec

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.