Two tug boats are towing a large boat, of mass m kg, back to shore. tug boat 1 is pulling with a force of t1 n at an angle of 25 degrees north of the forward motion and tug boat 2 is pulling with a force of t2 n at an angle of 25 degrees south of the forward motion. if the large boat is being pulled with constant velocity, and there is a resistive force of 4000n to the motion, then what are the magnitudes of the two forces t1 and t2?

For the answer to the question above asking f the large boat is being pulled with constant velocity, and there is a resistive force of 4000N to the motion, then what are the magnitudes of the two forces T1 and T2?
 T1 =T2 =4 000/2/cos(25)=
2206.75 N

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !