Satellite a orbits the earth at a height 3.00 times the earth's radius. satellite b orbits the earth at a height 2.00 times the earth's radius. what is the ratio of the period of satellite b to the period of satellite a?

a) 1 to √(3/2)^3

b) 1 to 3√(3/2)^2

c) 1 to √(2/3)^3

d) 1 to 3√(2/3)^2

*the "3√" represents a cubic root*
i think the answer is b, but i am not sure

A)1: √(3/2)^3

Explanation:

The formula for the period of the satellite is given by:

T = 2π √(r^3/GM)  

For satellite A,

T1 = 2π √((3r)^3/GM)  ………. (i)

For satellite B,

T2 = 2π √((2r)^3/GM) ……….. (ii)

Dividing equation (ii) by (i), we get

T2/T1  = √(2)^3/√(3)^3

Further Simplification results in

T2:T1 =1: √(3/2)^3

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

come closer and become far apart and become steam/gas