A30-n/c uniform electric field points perpendicularly toward the left face of a large neutral conducting sheet. the surface charge density in c/m2 on the left and right faces, respectively, are

Explanation:

As we know that electric field due to a large sheet is given by the formula

here we know that

= charge density

now we know that here the field is given for a point between two charged plates

so net electric field is given as

now here electric field is indicating towards left so here charge density on left side is negative while on right side it must be positive

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg