If you wished to warm 100 kg of water by 15 degrees celsius for your bath, how much heat would be required? (give your answer in calories and joules)

For the answer to the question above, 
Q = amount of heat (kJ) 
cp = specific heat capacity (kJ/kg.K) = 4.187 kJ/kgK 
m = mass (kg) 
dT = temperature difference between hot and cold side (K). Note: dt in °C = dt in Kelvin 

Q = 100kg * (4.187 kJ/kgK) * 15 K 
Q = 6,280.5 KJ = 6,280,500 J = 1,501,075.5 cal

Fitness is the ability to perform only very light levels of physical activity.