Apoint charge of +5 μc is located at the center of a sphere with a radius of 12 cm . what is the electric flux through the surface of this sphere ?

The formula of electric flux is:

electric flux = electric field * surface area
The surface area of a sphere is given by: 4*pi*r^2
Therefore: 4 * 3.14 * 12^2 is equal to 1808.64 cm^2, convert are to m^2
1808.64 cm^2 * (1 m/ 100 cm)^2 = 0.1808 m^2
The point charge is +5μC, convert this to electric field with units of V/m
then solve for the electric flux by multiplying the electric field with the surface area. 

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