If hst has a tangential speed of 7,750 m/s, how long is hst’s orbital period? the radius of earth is 6.38 × 106 m.

Assuming that earth is a perfect circle. First solve the circumference of the earth,

C = 2pi( r )

Where are is the radius

C = 2pi ( 6.38 x 10^6 m)

C = 4.01 x 10^7 m

O the orbital period

T = 4.01 x 10^7 m / 7,750 m/s

T = 5172.48 s

a.) travels faster in solids because the particles are closer together.

air is a gas water is a liquid

false.

explanation:

this statement is false. after falling for 5 seconds, its speed will not be 100 m/s.