Using hooke's law, f s p r i n g = k x , find the distance a spring with an elastic constant of 4 n/cm will stretch if a 2 newton force is applied to it.

a. 4 cm
b. 8 cm
c. 2 cm
d. 1/2 cm.

The correct answer is Option d.

Explanation:

Formula for Hooke's Law states that:

where, F = Force applied = 2N

k = spring constant = 4 N/cm

x = displacement of the spring from equilibrium position = ? cm

Putting values in above equation, we calculate the displacement or distance of the spring, we get:

Hence, the correct option is Option d.

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s