Ahot air balloon is flying above grovenburg. to the left side of the balloon, the balloonist measure the angle of depression to the groveburg soccer fields to be 20 degrees 15’. to the right side of the balloon, the balloonist measures the angle of depression to the high school football field to be 62 degrees 30’. the distance between the two athletic complexes is 4 miles.

Angle x = 90° - 22°15’  

Angle y = 90° - 62°30'

Angle z = 22°15’ = 22.25°

Angle w = 62°30’ = 62.50°

tan(z) = H/a => a = H/tan(z)

tan(w) = H/b => b = H/tan(w)

a+b = 4 => H/tan(z) + H/tan(w) = 4 => H [1/tan(z) + 1/tan(x) ] = 4

    H = 4 / {[1/tan(z) + 1/tan(x) ] } = 1.35 miles

    a = 1.35 / tan(22.25°) =  3.30 miles

    b = 4 – 3.30 = 0.7 miles

I hope it is very useful and you understand it. Let me know.

explanation:

considering the bohr theory, the type of connection that requires the transfer the answer conuldn't be right

attach the statements so i can answer : )